Optimal. Leaf size=145 \[ -\frac{2 \left (d^2-e^2 x^2\right )^{7/2}}{3 e (d+e x)^5}+\frac{14 \left (d^2-e^2 x^2\right )^{5/2}}{3 e (d+e x)^3}+\frac{35 \left (d^2-e^2 x^2\right )^{3/2}}{6 e (d+e x)}+\frac{35 d \sqrt{d^2-e^2 x^2}}{2 e}+\frac{35 d^2 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )}{2 e} \]
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Rubi [A] time = 0.0587709, antiderivative size = 145, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.167, Rules used = {663, 665, 217, 203} \[ -\frac{2 \left (d^2-e^2 x^2\right )^{7/2}}{3 e (d+e x)^5}+\frac{14 \left (d^2-e^2 x^2\right )^{5/2}}{3 e (d+e x)^3}+\frac{35 \left (d^2-e^2 x^2\right )^{3/2}}{6 e (d+e x)}+\frac{35 d \sqrt{d^2-e^2 x^2}}{2 e}+\frac{35 d^2 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )}{2 e} \]
Antiderivative was successfully verified.
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Rule 663
Rule 665
Rule 217
Rule 203
Rubi steps
\begin{align*} \int \frac{\left (d^2-e^2 x^2\right )^{7/2}}{(d+e x)^6} \, dx &=-\frac{2 \left (d^2-e^2 x^2\right )^{7/2}}{3 e (d+e x)^5}-\frac{7}{3} \int \frac{\left (d^2-e^2 x^2\right )^{5/2}}{(d+e x)^4} \, dx\\ &=\frac{14 \left (d^2-e^2 x^2\right )^{5/2}}{3 e (d+e x)^3}-\frac{2 \left (d^2-e^2 x^2\right )^{7/2}}{3 e (d+e x)^5}+\frac{35}{3} \int \frac{\left (d^2-e^2 x^2\right )^{3/2}}{(d+e x)^2} \, dx\\ &=\frac{35 \left (d^2-e^2 x^2\right )^{3/2}}{6 e (d+e x)}+\frac{14 \left (d^2-e^2 x^2\right )^{5/2}}{3 e (d+e x)^3}-\frac{2 \left (d^2-e^2 x^2\right )^{7/2}}{3 e (d+e x)^5}+\frac{1}{2} (35 d) \int \frac{\sqrt{d^2-e^2 x^2}}{d+e x} \, dx\\ &=\frac{35 d \sqrt{d^2-e^2 x^2}}{2 e}+\frac{35 \left (d^2-e^2 x^2\right )^{3/2}}{6 e (d+e x)}+\frac{14 \left (d^2-e^2 x^2\right )^{5/2}}{3 e (d+e x)^3}-\frac{2 \left (d^2-e^2 x^2\right )^{7/2}}{3 e (d+e x)^5}+\frac{1}{2} \left (35 d^2\right ) \int \frac{1}{\sqrt{d^2-e^2 x^2}} \, dx\\ &=\frac{35 d \sqrt{d^2-e^2 x^2}}{2 e}+\frac{35 \left (d^2-e^2 x^2\right )^{3/2}}{6 e (d+e x)}+\frac{14 \left (d^2-e^2 x^2\right )^{5/2}}{3 e (d+e x)^3}-\frac{2 \left (d^2-e^2 x^2\right )^{7/2}}{3 e (d+e x)^5}+\frac{1}{2} \left (35 d^2\right ) \operatorname{Subst}\left (\int \frac{1}{1+e^2 x^2} \, dx,x,\frac{x}{\sqrt{d^2-e^2 x^2}}\right )\\ &=\frac{35 d \sqrt{d^2-e^2 x^2}}{2 e}+\frac{35 \left (d^2-e^2 x^2\right )^{3/2}}{6 e (d+e x)}+\frac{14 \left (d^2-e^2 x^2\right )^{5/2}}{3 e (d+e x)^3}-\frac{2 \left (d^2-e^2 x^2\right )^{7/2}}{3 e (d+e x)^5}+\frac{35 d^2 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )}{2 e}\\ \end{align*}
Mathematica [A] time = 0.0972618, size = 87, normalized size = 0.6 \[ \frac{\frac{\sqrt{d^2-e^2 x^2} \left (229 d^2 e x+164 d^3+30 d e^2 x^2-3 e^3 x^3\right )}{(d+e x)^2}+105 d^2 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )}{6 e} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.051, size = 407, normalized size = 2.8 \begin{align*} -{\frac{1}{3\,{e}^{7}d} \left ( - \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) \right ) ^{{\frac{9}{2}}} \left ({\frac{d}{e}}+x \right ) ^{-6}}+{\frac{1}{{e}^{6}{d}^{2}} \left ( - \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) \right ) ^{{\frac{9}{2}}} \left ({\frac{d}{e}}+x \right ) ^{-5}}+4\,{\frac{1}{{e}^{5}{d}^{3}} \left ( - \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) \right ) ^{9/2} \left ({\frac{d}{e}}+x \right ) ^{-4}}+{\frac{20}{3\,{e}^{4}{d}^{4}} \left ( - \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) \right ) ^{{\frac{9}{2}}} \left ({\frac{d}{e}}+x \right ) ^{-3}}+8\,{\frac{1}{{e}^{3}{d}^{5}} \left ( - \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) \right ) ^{9/2} \left ({\frac{d}{e}}+x \right ) ^{-2}}+8\,{\frac{1}{e{d}^{5}} \left ( - \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) \right ) ^{7/2}}+{\frac{28\,x}{3\,{d}^{4}} \left ( - \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) \right ) ^{{\frac{5}{2}}}}+{\frac{35\,x}{3\,{d}^{2}} \left ( - \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) \right ) ^{{\frac{3}{2}}}}+{\frac{35\,x}{2}\sqrt{- \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) }}+{\frac{35\,{d}^{2}}{2}\arctan \left ({x\sqrt{{e}^{2}}{\frac{1}{\sqrt{- \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) }}}} \right ){\frac{1}{\sqrt{{e}^{2}}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.30443, size = 312, normalized size = 2.15 \begin{align*} \frac{164 \, d^{2} e^{2} x^{2} + 328 \, d^{3} e x + 164 \, d^{4} - 210 \,{\left (d^{2} e^{2} x^{2} + 2 \, d^{3} e x + d^{4}\right )} \arctan \left (-\frac{d - \sqrt{-e^{2} x^{2} + d^{2}}}{e x}\right ) -{\left (3 \, e^{3} x^{3} - 30 \, d e^{2} x^{2} - 229 \, d^{2} e x - 164 \, d^{3}\right )} \sqrt{-e^{2} x^{2} + d^{2}}}{6 \,{\left (e^{3} x^{2} + 2 \, d e^{2} x + d^{2} e\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (- \left (- d + e x\right ) \left (d + e x\right )\right )^{\frac{7}{2}}}{\left (d + e x\right )^{6}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: NotImplementedError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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